hoba
02-08-2012, 05:36 AM
Hey guys about the half shaft design i choose 4340 alloy steel and the diameter of the shaft will be 19.3 mm and it will be solid shaft the torque of the engine is 55 N.m and the reductions ratio will be 20.3 i want to know if my design is true or not?????
t=16T/pi*D^3
t=shear stress
T=total torque on the shaft
D=diameter of the shaft
i make the calculation and the t=776 Mpa
and the 4340 has a tensile strength of 861 MPa in the normalaized condition so its allowable shear strength will be 861*.66=568.26 MPa
so the design will not be safe
Can I heat treat the shaft to rise its tensile strength to 1800 and divided by 1.5(safety factor) and multiply it with .66(to convert it to shear strength ) the number will be 594 Mpa and it will be safe
plz help meeeee I think I do it the wrong way
t=16T/pi*D^3
t=shear stress
T=total torque on the shaft
D=diameter of the shaft
i make the calculation and the t=776 Mpa
and the 4340 has a tensile strength of 861 MPa in the normalaized condition so its allowable shear strength will be 861*.66=568.26 MPa
so the design will not be safe
Can I heat treat the shaft to rise its tensile strength to 1800 and divided by 1.5(safety factor) and multiply it with .66(to convert it to shear strength ) the number will be 594 Mpa and it will be safe
plz help meeeee I think I do it the wrong way