Erick Scarpone
07-09-2005, 04:13 PM
Hi I'm working on the selection of the tubing material for our next car... So basicaly I'm looking for less weight, good mechanical properties, and low cost. And that we can do the Safety Structure Equivalency Form if we get to use a diferent W.T. or O.D than the ones listed in rule 3.3.3.1.
So i made an Excel file with all the different W.T and O.D of 4130 in chassis shop, I was hoping to find out that I could use less O.D with the minimum W.T required by the rule 3.3.3.2.2 but to my surprise I just got that using O.D 1+1/8'' and W.T. 0.049 I comply with the minimum required buckling (E*I) and is actualy 0.086lb/ft less than using O.D. 1'' & W.T. 0.065 (Actually for the Side Impact proteccion it says that a minimun W.T of 0.049 but it does not comply with the E*I, at O.D of 1'')
For Bracing, harness Attachment Etc. I got to the conclusion that using the same O.D. 1+1/8 with W.T 0.049 wpold be the way to go less weight and still using 4130.
For the Front & Main Hoop I got that the way to go would be using O.D 1+1/8 and W.T 0.065 insted of using O.D 1'' and W.T of 0.095 couse I be saving 0.1823Lb/ft.
So my big question is WHAT IM I DOING WRONG??? I'm asuming that something is wrong because i did not saw cars with tubing of big Outside Diameters at the competition. Then I Started thinking that maybe people would use minor O.D and really big W.T but this configuration does not save weight, and doing some resarch I read about that in the second moment of inertia if the mass is way more far of the deforming axis it is better for torsional stiffnes (For Example is better for Torsional Stiffnes a round hollow tube than a round solid bar).
Anyway I'm watching that using chromoly and SAE1010 the add up the same weight, and SAE 1010 is cheaper. So what are the real advantages of using chromoly?
Im using the area inertia ecuation of (Weakest axis)Ix=pi/64*(O.D^4-I.D^4) and E is very similar for SAE 1010 and Chromoly?
Help please Help!!!
Sorry for the lenght of the post but I do need help and whant people to understand my situation thanks!!!
So i made an Excel file with all the different W.T and O.D of 4130 in chassis shop, I was hoping to find out that I could use less O.D with the minimum W.T required by the rule 3.3.3.2.2 but to my surprise I just got that using O.D 1+1/8'' and W.T. 0.049 I comply with the minimum required buckling (E*I) and is actualy 0.086lb/ft less than using O.D. 1'' & W.T. 0.065 (Actually for the Side Impact proteccion it says that a minimun W.T of 0.049 but it does not comply with the E*I, at O.D of 1'')
For Bracing, harness Attachment Etc. I got to the conclusion that using the same O.D. 1+1/8 with W.T 0.049 wpold be the way to go less weight and still using 4130.
For the Front & Main Hoop I got that the way to go would be using O.D 1+1/8 and W.T 0.065 insted of using O.D 1'' and W.T of 0.095 couse I be saving 0.1823Lb/ft.
So my big question is WHAT IM I DOING WRONG??? I'm asuming that something is wrong because i did not saw cars with tubing of big Outside Diameters at the competition. Then I Started thinking that maybe people would use minor O.D and really big W.T but this configuration does not save weight, and doing some resarch I read about that in the second moment of inertia if the mass is way more far of the deforming axis it is better for torsional stiffnes (For Example is better for Torsional Stiffnes a round hollow tube than a round solid bar).
Anyway I'm watching that using chromoly and SAE1010 the add up the same weight, and SAE 1010 is cheaper. So what are the real advantages of using chromoly?
Im using the area inertia ecuation of (Weakest axis)Ix=pi/64*(O.D^4-I.D^4) and E is very similar for SAE 1010 and Chromoly?
Help please Help!!!
Sorry for the lenght of the post but I do need help and whant people to understand my situation thanks!!!